数学二公式
\lim_{x\to0} \frac{\sin x}{x} = 1
\lim_{x\to oo} (1+\frac{1}{x})^x = e
\lim_{x\to 0} (1+x)^\frac{1}{x} = e
x\rightarrow 0
\lim_{x\to0} \frac{\sin x}{x} = 1
\lim_{x\to oo} (1+\frac{1}{x})^x = e
\lim_{x\to 0} (1+x)^\frac{1}{x} = e
x\rightarrow 0
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